Question

Frame a quadratic polynomial, whose zeroes are 3 and -1

Answer 1

here is your answer, mate

Answer 2

let ...

$\alpha = 3$

&

$\beta = - 1$

sum of zeros

$\alpha + \beta = 3 + ( - 1)$

$\alpha + \beta = 2$

Product of zeros

$\alpha \beta = 3( - 1)$

$\alpha \beta = - 3$

Required Quadratic Polynomial

${x}^{2} - ( \alpha + \beta )x + \alpha \beta$

${x}^{2} - 2x + ( - 3)$

${x}^{2} - 2x - 3$