Question

Frame an equation from the following information
Rate of jaggery per kilo is * 9 more than the rate of suger. The product of their raten
is 1786. Find their rates,​

Answer 1

Answer:

x×x+9-1786=0

Step-by-step explanation:

let

Rate of sugar be x

according to problem,

Rate of jaggery = x+9

The products of their rates = 1786

i.e. x×x+9 = 1786

x×x+9-1786 =o

Answer 2

Answer: Rate of sugar =38₹. And Rate of jagarry= 47₹

Step-by-step explanation:

Let the rate of sugar be x₹/kg.

According to given information

Rate of jagarry= (x+9)

∴ (x) (x+9) =1786 ------given

x²+9x-1786=0---------(1)

Let's solve equation by formula method.

Comparing x²+9x-1786=0 with ax²+bc+c=0

∴ we get , a=1, b=9, and c= -1786

∴b²-4ac= (9)2-4(1)(-1786)

= 81+7144

= 7225

∴ x= -(b) +- √b2-4ac/2a

= -9 +- √7225/2

= -9 +- 85/2

∴x= -9-85/2 or x=-9+85/2

x= -94/2 or x=76/2

X= -47 or X= 38

But rate never negative.

∴ X=38

∴Rate of jagarry=x+9

= 38+9

=47₹

∴ The rate of sugar and jagarry are 38₹/kg and 47₹/kg respectively.

Thank you!