Question

frame quadratic polynomial whose zeroes are 2 and±3

Answer 1

$\alpha = 2 \: \: and \: \: \beta = 3$

quadratic polynomial is :-

${x}^{2} - (sum \: of \: zeros)x + product \: of \: \: zeros$

sum of zeros = 5

product of zeros = 6

${x}^{2} - 5x + 6 = 0$

this is the required quadratic polynomial.

Answer 2

hey...

sum of zeroes= 2+3=5

2-3=-1

product of zeroes=2×3=6

2×-3=-6

x^2 - ( sum of zeroes)x + product of zeroes

=x^2-5x+6

=x^2+x-6

these are two quadratic equations.