Math, asked by Nabhankhan97451, 4 months ago

Frame the equation and solve:

a) Sum of a number and 7 is equal to 15. What is the number?

b) 6 times a number added to 10 is 58

c) Sum of two consecutive natural numbers is 5.​

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Answers

Answered by MJRISHWANTH
1

Answer:

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Answered by bhatnagarbhuvi24
0

Answer:

let the number which is to be found be x in each case

a)x+7=15

x=15-7

x=6

b)6×x+10=58

6x+10=58

6x=58-10

6x=48

x=48÷6

x=8

c)Any two consecutive numbers are going to be nn and n+1.n+1. Subtract 11 from 55, and then divide it in half.

n+n+1=5n+n+1=5

(2n+1)−1=5−1⟹(2n+1)−1=5−1

2n2=42⟹2n2=42

n=2 n+1=3n=2 n+1=3

Step-by-step explanation:

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