Frame the equation and solve:
a) Sum of a number and 7 is equal to 15. What is the number?
b) 6 times a number added to 10 is 58
c) Sum of two consecutive natural numbers is 5.
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let the number which is to be found be x in each case
a)x+7=15
x=15-7
x=6
b)6×x+10=58
6x+10=58
6x=58-10
6x=48
x=48÷6
x=8
c)Any two consecutive numbers are going to be nn and n+1.n+1. Subtract 11 from 55, and then divide it in half.
n+n+1=5n+n+1=5
(2n+1)−1=5−1⟹(2n+1)−1=5−1
2n2=42⟹2n2=42
n=2 n+1=3n=2 n+1=3
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