Frame the equation from the roots of the equation.
2-3√5, 2+3√5
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Answer:
Let 'm' and 'n' be the roots ∴m=3+2
5
and n=3−2
5
Sum of the roots =m+n=3+2
5
+3−2
5
∴m+n=6
Product of the roots =mn=(3+2
5
)(3−2
5
)=(3)
2
−(2
5
)
2
=9−20∴mn=−11
x
2
−(m+n)x+mn=0∴x
2
−6x−11=0
Step-by-step explanation:
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