Math, asked by dishanidps2641, 1 month ago

Frank needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 52​-by-52-m square. Frank says the area is m. Find the area enclosed by the figure. Use 3.14 for . What error might Frank have​ made?
(8-6: MathXL for School: Practice & Problem Solving)

Answers

Answered by janvipandita672
0

Answer:

the cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areathe cross section of a cylinder is a regular hexagon of side 4cm and its height measures 12cm. Then its total surface areaThe area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

The area of the cross section = area of the trapezium

= 12 (10 + 6)8 cm2

= 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

= 64 cm2 × 20 cm

= 1280 cm3

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