Question

Free-body diagrams for four situations are shown below. The net force is known for each situation. However, the magnitudes of a few of the individual forces are not known. Analyze each situation individually and determine the magnitude of the unknown forces.

Answer 1

Answer:

Figure 1: A=50 N Left and B=200 N Up  

Figure 2: C=1100 N Up  

Figure 3: E=300 N, Down and D=20 N, Right

Figure 4: F=H and G=50 N, Right

Explanation:

We are given four diagram of forces on blocks.  

Free-body diagrams for four situations are shown in attachment.  

The net force is known for each situation.

Figure 1: $F_{net}=0\ N$

Net force on body is 0  

Net Vertical and Horizontal force must be zero.  

Therefore, A=50 N Left and B=200 N Up  

Figure 2: $F_{net}=900\text{ N, Up}$

Two force on body, C Up and 200 N down.  

Net force = C-200  

C-200 = 900

Therefore, C=1100 N Up  

Figure 3: $F_{net}=60\text{ N, Left}$

Vertical forces: 300 N, Up and E down.  

Here vertical force is zero.

Therefore, E-300 = 0  

E=300 N, Down  

Horizontal force is 60 N, Left

80-D=60

Therefore, D=20 N, Right

Figure 4: $F_{net}=30\text{ N, Right}$

Vertical force is zero.  

Therefore, F=H

Net horizontal force is 30 N, Right

Therefore, G-20=30  

G=50 N, Right

Answer 2

"Answer:

1 .

$F_{Net} = 0 = 50-A$

A=50 Newton as it balances the other on right side

$F_{Net} = 0 = B-200$

B = 200 Newton

2.

$F_{Net} =900up$

so, 900=C-200

C = 1100N

3.

$F_{Net} =60N left$

$F_{Y_{Net}} =0$

0=300-E

E=300N

$F_{X_{Net}} =-60N$

-60 =-80 + D

D = 20N

4.

$F_{Net} =30N right$

$F_{y_{Net}} = 0 = F = H$

$F_{X_{Net} = 30$

30 = G - 20

G = 50N

  Force is an influence which can change the state of an object. It has both direction and magnitude, so it is a vector quantity. The unit of force is Newton. There are many types of force acting on the object."