Question

FREE BRAINLIEST!! But correct answer first>>A bungee cord has a spring constant of 82.5N/m. After jumping, a person oscillates with a period of 7.50s what is the mass of the person? (Unit=kg)

Answer 1

Given :

Spring constant of the bungee cord = 82.5 N/m

Time period of the oscillation = 7.50 s

To Find :

What is the mass of the person ?

Solution :

We know that the angular frequency of oscillation is given as :

$\omega = \sqrt{\frac{K}{m}}$

Here , K is spring  constant of bungee cord  and m is mass of the person .

Also we have :

$\omega = \frac{2\pi }{T}$

  = 0.84

So,

$0.84 = \sqrt{\frac{K}{m}}$

Or, $(0.84)^2 = {\frac{82.5}{m}}$

Or, m = $\frac{82.5}{(0.84)^2}$

Or, m =116.92

Hence , the mass of the person is 116.92 kg .