free breaker supplied produce an acceleration of 6 metre per square in opposite direction to the motion of the car takes 2 hours to stop after the application of brakes calculate the distance travelled by the car driving his time.
Answers
Answered by
1
Let the car be travelling with a speed 'u'
The car stops after 2 hours(7200 seconds) after the application of brakes with a decceleration of 6 metres per second square.
The final velocity of the car is zero.
now, applying newtons laws of motion;
v = u + at
0 = u + (-6)(7200)
u = 43200 m/s
again, s = ut + 1/2at^2
s = 43200(7200) + 1/2(-6)(7200)^2
s = 311040000 - 155520000
s = 155520000 metres
s = 1,55,520 kilometres
The car stops after 2 hours(7200 seconds) after the application of brakes with a decceleration of 6 metres per second square.
The final velocity of the car is zero.
now, applying newtons laws of motion;
v = u + at
0 = u + (-6)(7200)
u = 43200 m/s
again, s = ut + 1/2at^2
s = 43200(7200) + 1/2(-6)(7200)^2
s = 311040000 - 155520000
s = 155520000 metres
s = 1,55,520 kilometres
Similar questions