❤FREE POINTS❤
Maths ch1 SM pg1.37 Q.20
If (5.678)^x=(0.5678)^y=10^z then
Plz. explain in detail step by step
Answers
Hey Mate here is your answer ✌️☺️
Answer:
Required correct option is option ( b ).
Step-by-step-explanation:
Given : ( 5.678 )^x = ( 0.5678 )^y = 10^z .
Let the given terms are also equal to k.
Thus,
= > ( 5.678 )^x = ( 0.5678 )^y = 10^z = k
Then,
Case 1 : where ( 5.678 )^x = k
= > ( 5.678 )^x = k
= > 5.678 = k^( 1 / x ) ...( 1 )
Case 2 : where ( 5.678 )^x = k
= > ( 0.5678 )^y = k
= > 0.5678 = k^( 1 / y ) ...( 2 )
Case 3 : where 10^z = k
= > 10^z = k
= > 10 = k^( 1 / z ) ...( 3 )
Multiplying ( 1 ) & ( 3 ) and dividing by ( 2 ) : -
= > ( 5.678 × 10 / 0.5678 ) = [ k^( 1 / x ) × k^( 1 / z ) ] / [ k^( 1 / y ) ]
= > 100 = k^{ 1 / x + 1 / z - 1 / y ]
= > 10^2 = k^( 1 / x + 1 / z - 1 / y ]
= > { k^( 1 / z )}^2 = k^( 1 / x + 1 / z - 1 / y ) { from ( 3 ), 10 = k^( 1 / z ) }
= > k^( 2 / z ) = k^( 1 / x + 1 / z - 1 / y )
= > 2 / z = 1 / x + 1 / z - 1 / y
= > 0 = 1 / x + 1 / z - 2 / z - 1 / y
= > 0 = 1 / x - 1 / z - 1 / y
Hence the required correct option is ( b ).