Freely falling body has velocity v after it falls through a height h .The distance it has to fall down further for its velocity to become double is
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v^2 = 2 g h as u = 0 for freely falling body.
For velocity to be double, height dropped/ distance h has to be 4 times.
So the body has to fall further 3 h distance.
For velocity to be double, height dropped/ distance h has to be 4 times.
So the body has to fall further 3 h distance.
kvnmurty:
Click on the red hearts thanks above
The question states that it has already fallen a height so it must have achieved a velocity. So we cant say that u is 0
u = 0 is the i initial at t=0... Velocity is v (not u) after falling height h and at time t = v/g.
Velocity = 2v after falling a further 3h ie. After falling total 4h distance.
I took v as initial velocity for that time frame
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