Question

freely falling body reach the ground in t seconds the average velocity during its following is​

Answer 1

Answer:

u = 0

time = t secs

a = g

Using Newton's Second equation of motion,

s = ut + 1/2 at^2

= 0(t) + 1/2gt^2

s = gt^2/2

Avg. velocity = total displacement/total time

<v> = gt^2/ 2t

<v> = gt/2

Hence, gt/2 is correct.

Explanation:

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