Question

Freqency of dominant allele is 0.6 find heterozygous frequency

Answer 1

Answer:

0.48

Explanation:

here p = 0.6

then p2 = 0.36

q = 0.4

then q2 = 0.16

Now according to herdy Weinberg equation we know : p2+2pq+q2 = 1

then , here 2pq = 1-(0.36+0.16 )

= 0.48