Question

frequency of radiation of the emission spectrum when electron present in hydrogen atom undergoes Transition from n= 3 energy level to the ground state​

Answer 1

Given :

Electron present in hydrogen atom undergoes transition from n = 3 energy level to the ground level to the ground state.

To Find :

Frequency of radiation of the emission spectrum.

Solution :

❒ Frequency of radiation of emmision spectrum when electron of hydrogen atom undergoes transition from n₂ state to n₁ (n₂ > n₁) state is given by

$\bf:\implies\:\underline{\boxed{\bf{\purple{\nu=3.29\times10^{15}\bigg(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\bigg)\:Hz}}}}$

By substituting the given data,

$\sf:\implies\:\nu=3.29\times10^{15}\:\bigg(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\bigg)$

• n₁ = 1
• n₂ = 3

$\sf:\implies\:\nu=3.29\times10^{15}\:\bigg(\dfrac{1}{1^2}-\dfrac{1}{3^2}\bigg)$

$\sf:\implies\:\nu=3.29\times10^{15}\:\bigg(1-\dfrac{1}{9}\bigg)$

$\sf:\implies\:\nu=3.29\times10^{15}\:\bigg(\dfrac{9-1}{9}\bigg)$

$\sf:\implies\:\nu=\dfrac{(3.29\times10^{15})\times8}{9}$

$\sf:\implies\:\nu=\dfrac{26.32\times10^{15}}{9}$

$:\implies\:\underline{\boxed{\bf{\red{\nu=2.92\times10^{15}\:Hz}}}}$