Question

Frequency of tuning fork a and b 3% and 2% less han tuning fork c a and b produce 5 beats per second frequency of tuning fork a is

Answer 1

Answer:

=3648%

Explanation:

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Answer 2

Answer:

$a = 485Hz$

Explanation:

Let the frequencies of tuning fork a,b and c be a,b and c respectively

Since a and b are 3% and 2% less than c

$a=c-\frac{3}{100}c\\\\ a=\frac{97}{100}c----(1)\\ \\b=c-\frac{2}{100}c\\ \\b=\frac{98}{100}c----(2)$

Since a and b produce 5 beats together,

$b-a=5----(3)$

From(1) , (2) and (3)

$5=\frac{(98-97)c}{100}$

$c=500Hz$

$a=\frac{97}{100}(500)$  [From (1)]

$a=485Hz$

Hope this answer helped you :)