Biology, asked by patleravikiran123, 7 months ago

frequency ofa perfect heterozygous cross between AABBCC×AaBbCc is

Answers

Answered by ReRepeater

1

Answer:

Frequency = 1/8

Explanation:

total gamates are 8 (2^n)

Out of the total, only 1 gamate forms abc

So complete heterozygous condition is for 1/8

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