friction Q. A block of mass 5kg is on a rough horizontal surface and is at rest. Now a force of 24N is imparted to it with negligible impulse. If the coefficient of kinetic friction is 0.4 and g=9.8 m/s, then the acceleration of the block is 0.88m/s
Answers
As per the question, the mass of the block m = 5 kg.
The applied force F = 24 N.
It is given that acceleration due to gravity g =
The coefficient of kinetic friction
Hence, the frictional force acting on the block is calculated as -
Frictional force f =
=
= 19.6 N.
The net force acting on the particle
= 24 N - 19.6 N
= 4.4 N.
We are asked to calculate the acceleration of the block.
From Newton's second law, we know that net force acting on particle is the product of mass with the acceleration .
Mathematically
Hence, the acceleration of the block is