Frictional force acting between the blocks at t=3s in the arrangements shown is (sin 37 = 3/5, cos37 = 4/5)
F= 20N
U=0.06
2kg
4kg
Smooth
Answers
Answered by
0
Answer:
good question but I didn't know the answer because I M in 7 class.
Explanation:
nahi patta
Similar questions