Question

frictional force of air on a body of mass 0.25kg falling with acceleration of 9.2m/s

Answer 1

net force on body=mg-resistance
=mg-f=ma

0.25*9.8-f=0.25*9.2
f=0.25*0.6=0.150N

Answer 2

Given that,

Mass of a body, m = 0.25 kg

Acceleration of the body, a = 9.2 m/s²

To find,

The frictional force of air on a body.

Solution,

When the body is falling with some acceleration, the net force acting on it is given by :

F = m(g-a)

g is the acceleration due to gravity

So,

$F = 0.25\times (9.8-9.2)\\\\F=0.15\ N$

So, the frictional force of air on the body is 0.15 N.