Question

friend help me differential equations ​

Answer 1

cosx- sinx this is can be the answer of your question

Answer 2

Answer:

The result of the given function after differentiating is:

$y'=cosx-sinx$

Step-by-step explanation:

Given function to be differentiate is:

$y=sinx+cosx$

Hence differentiating it with respect to x we get:

$\dfrac{d}{dx}(y)=\dfrac{d}{dx}(sinx+cosx)\\\dfrac{dy}{dx}=\dfrac{d}{dx}(sinx)+\dfrac{d}{dx}(cosx)$

We may write:

$\dfrac{dy}{dx}=y'$

Hence above function will become as:

$y'=cosx-sinx$