friend mante ho toh pakka poora solve karoge.....
The polynomial 4x^4+2x^3-2x^2+x-1 when divided by x^2+2x-3 gives the remainder px+q.find the value of p and q....
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Answered by
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Given f(x) = 4x^4 + 2x^3 - 2x^2 + x - 1.
Given g(x) = x^2 + 2x - 3.
We need to divide f(x) by g(x).
4x^2 - 6x + 22
-----------------------------------------
x^2 + 2x - 3)4x^4 + 2x^3 - 2x^2 + x - 1
4x^4 + 8x^3 - 12x^2
-----------------------------------------
-6x^3 + 10x^2 + x - 1
-6x^3 - 12x^2 + 18x
--------------------------------------------
22x^2 - 17x - 1
22x^2 + 44x - 66
-----------------------------------------------
-61x + 65
The remainder obtained = -61(x) + 65.
= px + q.
Therefore the value of p = -61, q= 65.
Hope this helps!
Given g(x) = x^2 + 2x - 3.
We need to divide f(x) by g(x).
4x^2 - 6x + 22
-----------------------------------------
x^2 + 2x - 3)4x^4 + 2x^3 - 2x^2 + x - 1
4x^4 + 8x^3 - 12x^2
-----------------------------------------
-6x^3 + 10x^2 + x - 1
-6x^3 - 12x^2 + 18x
--------------------------------------------
22x^2 - 17x - 1
22x^2 + 44x - 66
-----------------------------------------------
-61x + 65
The remainder obtained = -61(x) + 65.
= px + q.
Therefore the value of p = -61, q= 65.
Hope this helps!
Aisha1000:
please please
Answered by
1
Ans. is p = (-62) and q = 65 .. solution is in the pic ... :)
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