Question

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Answer 1

Answer:

NICE 30∘ in (1), we  get,

(2y+2×30)∘=160∘

⇒(2y+60)∘=160∘

⇒(2y)∘=100∘

⇒y∘=50∘.

So, ∠A=(2x−10)∘=(2×30−10)∘=(60−10)∘=50o

∠B=(2y−20)∘=(2×50−20)∘=(100−20)∘=80o

∠C=(2y+30)∘=(2×50+30)∘=(100+30)∘=130o 

and ∠D=(3x+10)∘=(3×30+10)∘=(90+

Answer 2

Answer:

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