Math, asked by Anonymous, 2 days ago

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Answered by BrainlyPrivacy
28

Answer :

  • Present age of son is 7.5 years
  • Present age of father is 52.5 years

Given :-

  • A fether is 45 years elder than his son.
  • In 15 years, the father will be three times as old as his son.

To Find :-

  • Their present age ?

Solution :-

  • Let present age of son be y years.
  • As it is stated question that a father is 45 years elder than his son. So, present age of father will be (y + 45) years.

Their ages after 15 years :

  • Age of son = (y + 15) years
  • Age of father = y + 45 + 15 = (y + 60) years.

According to the Question :

  • In 15 years, the father will be three times as old as his son.

Therefore,

➻ Age of father = 3(Age of son)

➻ y + 60 = 3(y + 15)

➻ y + 60 = 3y + 45

➻ y - 3y = 45 - 60

➻ -2y = -15

➻ 2y = 15

➻ y = 15/2

y = 7.5 years

  • Hence, present age of son 7.5 years.

Now we know that,

➻ Present age of father = (y + 45) years

• Putting y = 7.5 we get,

➻ Present age of father = (7.5 + 45) years

Present age of father = 52.5 years

  • Hence, present age of father is 52.5 years.

Verification :-

  • We know that according to the question, in 15 years, the father will be three times as old as his s,,on.

Therefore,

➻ Age of father = 3(Age of son)

➻ y + 60 = 3(y + 15)

• Putting y = 7.5 we get,

➻ 7.5 + 60 = 3(7.5 + 15)

➻ 67.5 = 3(22.5)

➻ 67.5 = 3 × 22.5

➻ 67.5 = 67.5

LHS = RHS

  • Hence, verified.

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Answered by kevin7489
0

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