Friends can you please solve the question please
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Answered by
1
Answer:
A (ΔABC) = 1/2 * AC * BM
= 1/2 * 22 * 3
= 11 * 3
= 33 cm sq.
A (ΔADC) = 1/2 * AC * DN
= 1/2 * 22 * 3
= 11 * 3
= 33 cm sq.
Area of quadrilateral ABCD = A (ΔABC) + A (ΔADC)
= 33 + 33 = 66 cm sq.
Hope it helps...
Answered by
1
Answer:
In triangle ABC -
Ar (ABC)= 1/2 ×Base×Height
= 1/2 × AC × BM. ----1
Ar (ADC)=1/2 ×Base ×Height
=1/2×AC×DN------2
By 1 + 2-
Ar (ABC) + Ar (ADC)= 1/2 × AC × (BM+DN)
Ar (ABCD) = 1/2 × 22 × (3+3)
= 1/2 × 22 × 6
= 22×3
=66 cm square
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