Question

Friends can you solve this sum for me
And I need the solved and proper answer ​

Answer 1

find the area of triangle ABC and the

value of x for the following Triangle

Area of triangle ABC = 3√7 cm^2 and the value of x = √7 cm

Given,

As, LBPC = 90°

... A BPC is a right angled triangle.

→ BC^2= BP^2 + PC^2

→ BC^2 = (AB/2)^2 + PC^2

→ 4^2= (6/2)^2 + x^2

⇒ x^2 = 16-9=7

• :•x = √7

As, ZAPC = 90°

. .. A APC is a right angled triangle.

→ AC^2 = AP^2 + PC^2

→ AC^2 = 3^2 + (√7)^2

→ AC^2 = 9+7

→ AC^2 = 16

. .. AC = 4 cm

Here, BC = AC = 4cm and AB = 6 cm

We can notice that, since the

triangle has 2 sides equal, therefore it should be an isosceles triangle. Area of isosceles triangle

A = bh/2

= (6* √7)/2

= 3√7 cm^2

hope it helps you

please mark me as brainliest

Answer 2

Step-by-step explanation:

aqc is angle of 90°

ab =6cm

bc=4cm

aq=3 cm

6+4+3

ans 13 cm

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