friends give this 3 answer I will mark a brainlist please help me
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Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
∠BAC + ∠ABC + ∠ACB = 180° (Angle sum property of a triangle)
⇒ ∠BAC + 69° + 31° = 180°
⇒ ∠BAC = 180° − 100º
⇒ ∠BAC = 80°
∠BDC = ∠BAC = 80° (Angles in the same segment of a circle are equal)
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mean=23
total no. of observations==15
so,sum=mean*total no. of observations
sum=23*15
sum=345
new sum=initial sum*2
new sum=345*2=690
new mean=new sum/total no. of observations
new mean=690/15=46
hope it helps....!!