Question

friends no one is able to answer this question. if any one can then solve it with step by step

Answer 1

Given that A and B can do a work in 18 days.

( A + B)'s 1-day work = 1/18.


Given that B and C can do a work in 30 days.

(B+C)'s 1-day work = 1/30.


Given that A and C can do a work in 45/2 days.

(C + A)'s 1-day work= 2/45 days.


Now,

On adding all the 3equations, we get

2(A + B + C)'s 1-day work = 1/18 + 1/30 + 2/45

                                          = 12/90

                                          = 2/15.


(A + B + C)'s 1-day work = 2/30.


A's individual work = 2/30 - 1/30

                                = 1/30.



B's individual work = 2/30 - 2/45

                                = $\frac{1}{15} - \frac{2}{45}$

                                $= \frac{1 * 3 }{45} - \frac{2}{45}$

                                $= \frac{1 * 3 - 2}{45}$

                                $= \frac{3 - 2}{45}$

                                1/45



C's individual work = 2/30 - 1/18

                                 = 1/90.



Therefore:

A can do the work in 30 days.

B can do the work in 45 days.

C can do the work in 90 days.


Hope this helps!