Question

friends please answer it then I mark as brainlist step by step explanation​

Answer 1

Your Answer:

i)

$\tt 3x + 6 \\\\ Taking \:\:Common \:\:as \:\:3 \\\\ \tt = 3(x +2)$

So, the factors are 3 and (x+2)

(ii)

$\tt 2x^2+3xy \\\\ Taking \:\: Common \:\:as \:\: x \\\\ \tt = x(2x+3y)$

So, the factors are x and (2x+3y)

iii)

$\tt 4x^2y^2-6x^2y \\\\ \tt Taking \:\:Common \:\: as \:\:2x^2y \\\\ \tt = 2x^2y(2y -3)$

So, the factors are 2x^2y and (2y-3)

iv)

$\tt 2x^3+4x^2+6x \\\\ \tt Taking\:\: Common\:\:as\:\:2x \\\\ \tt= 2x(x^2+2x+3)$

So, the factors are 2x and (x^2 + 2x + 3)

Concepts Used:-

• Factorization
• Taking Common