Friends please answer my question. What is middle term splitting in factorisation?
Answers
Answer:
factorization main theme is to split given expression as the product of some variables or monomials...
if we one example
x^2+5x+6
if 5x split as 4x+x there is no use..
by splitting 5x as 2x and 3x only the factors may get...
here we should compare the product of (x^2 term and constant term )
here 1 and 6...so we can Assume splitting terms product is equal to the x^2 term and constant term
x^2+3x+2x+6
x(x+3)+2(x+3)
here we get common factor (x+3)
then only we can write as ..
(x+3)(x+2)
...if we split 6x as 5x and x we can't get like above...
hope ig helps you
Middle term splitting is in the form of ax²+bx + c, where a, b and c are constant integers and x is a variable. To factorise this expression, we have to find two numbers such that their product is the product of a and c and the sum or difference of the two numbers is equal to b.
EXAMPLE:
x²+11x+30
we have to find two numbers whose sum is 11 and product is 30*1= 30.
clearly those numbers are 6 and 5.
x²+6x+5x+30
x(x+6)+5(x+6)
(x+6)(x+5)
hopes it helps!