Question

friends please answer this question​

Answer 1

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$\\ \implies \sf \: perimeter \: of \: field \: = 2(l + b)$

$\\ \implies \sf \: perimeter \: of \: field = 2(51 + 40)$

$\\ \implies \sf \: perimeter \: of \: field \: = 2 \times 91$

$\\ \implies \sf \: perimeter \: of \: field \: = 182m \:$

$\\ \therefore \: \sf \: cost \: of \: fencing \: = 182 \times 50$

$\implies \sf \: cost \: of \: fencing = 9100$

$\\ \implies\sf{cost \: of \: fencing= Rs 9100}$

$\implies \bf \: total \: cost \: = 71400$

$\mapsto \bf \: rate \: = 35 \: {m}^{ - 2}$

$\\ \implies \sf \therefore \: area = \frac{total \: cost}{rate}$

$\\ \implies \sf \: rate \: = \frac{71400}{35} = 2040 {m}^{2}$

$\\ \implies \sf \: length \: \times \: width \: = 2040$

$\\ \implies \sf \: length \times \: 40 = 2040$

$\\ \implies \sf \: length \: = \frac{2040}{40} = \frac{204}{4} = 51$

$\\ \implies \sf \: length \: = 51m$

$\therefore \boxed{ \sf{length \: = 51m}}$

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