Question

friends, please help​

Answer 1

for equal roots of quadratic equation:

b^2 -4ac=0

or b^2 =4ac

Here, a=(z-2), b=-(5+z), c=16

Put these values in above

[ -(5+z) ]^2 =4(z-2)×16

25+z^2 +10z=64z-128

z^2 -54z+153=0

z^2 -51z-3z+153=0

z(z-51) -3(z-51) =0

(z-51)(z-3) =0

so, z=51, or 3 Ans.

please mark as brainliest✌❤

Answer 2

Answer:

here is the answer mark as brainliest

Step-by-step explanation:

z=51 or else answer 3