Question

friends please help me with these problems with steps​

Answer 1

Answer:

Given,

Effort = 15 kgf

Load arm = 100 cm

Effort arm = 40 cm

Mechanical advantage = Effort arm/Load arm = 40/100 = 0.4

By definitions,

Mechanical advantage = Load/Effort

∴ 0.4 = Load/15 kgf

⇒ Load = 15 kgf × 0.4

∴ Load = 6 kgf

Explanation: answer in breif

Given

A lever of length 100 cm has effort of 15 kgf at a distance of 40 cm from the fulcrum at one end.

We Find

What load can be applied as its other end

According to the question

Mechanical Advantage = Effort Arm / Load Arm

= 40/100

= 0.4

So,

0.4 = Load / 15 KGF

= Load = 15 × 0.4 kgf

= Load = 6 kgf

so, Load is 6 kgf