Question

Friends please help me with this question ...

Answer 1

hii friend
good evening !!!


sin theta = cos theta

tan theta = sin theta / cos theta = sin theta / sin theta

tan theta = 1
theta = 45°

in question

2tan square theta + sin square theta - 1
= 2 tan square 45° + sin square 45° - 1
= 2(1) square + (1/√2) square - 1
= 2 + 1/2 - 1
= 1+1/2
= 3/2

here's your answer!!!

Answer 2

Hey !!!


sin¢ = cos¢ ( given )

And ¢ is 0°< ¢ <90°

hence

sin¢ = cos¢ (given)

since ,

sin¢ = sin ( 90° - ¢ ) { •°• cos¢ = sin(90° - ¢ )


¢ = 90° - ¢

2¢ = 90°

¢ = 90°/2 = 45°

From question .

2tan²¢ + sin²¢ - 1

2 tan²45° + sin²45°-1 [ putting the value of ¢]

but , tan45° = 1
sin45° = 1/√2

since,

2× 1 + ( 1/√2)² - 1

2 + 1/2 - 1

4 + 1 - 2 / 2

3/2 Answer ✔

_______________________

Hope it helps you !!!

@Rajukumar111