Question

friends..!
Please solve this..!

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Answer 1

Hey your answer is in picture.

hope it helps you.......

Answer 2

Question:

Solve:

5/(x-1) + 1/(y-2) = 2 and 6/(x-1) - 3/(y-2) = 1 .

Answer:

x = 4

y = 5

Solution:

We have;

5/(x-1) + 1/(y-2) = 2 --------(1)

6/(x-1) - 3/(y-2) = 1 ---------(2)

Now,

Multiplying both sides of eq-(1) by 3 , we get;

=> 3•[5/(x-1) + 1/(y-2)] = 3•2

=> 15/(x-1) + 3/(y-2) = 6 --------(3)

Now,

Adding eq-(2) and eq-(3) , we get;

=> 6/(x-1) - 3/(y-2) + 15/(x-1) + 3/(y-2) = 1 + 6

=> 21/(x-1) = 7

=> (x-1) = 21/7

=> x - 1 = 3

=> x = 3 + 1

=> x = 4

Now,

Putting x = 4 in eq-(2) , we get;

=> 6/(x-1) - 3/(y-2) = 1

=> 6/(4-1) - 3/(y-2) = 1

=> 6/3 - 3/(y-2) = 1

=> 2 - 3/(y-2) = 1

=> 3/(y-2) = 2 - 1

=> 3/(y-2) = 1

=> 3 = y - 2

=> y = 3 + 2

=> y = 5

Hence,

The solution of the given system of the equations is ;

x = 4 , y = 5