Friends please solve this question. it's very very important. I need it very very much-
A cuboidal fish tank has a length of 30 cm, a breadth of 20 cm and a height of 20 cm. The tank is placed on a horizontal table and it is three-quarters full of water. Find the area of the tank which is in contact with water.
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The Length and Breath Covered By Water is equal as Tank's Length and Breath.
i.e., L= 20cm B = 20cm
But Height is 3/4 th ( three-quarters ) of Tank's Height
So, H = 20×3/4 = 15cm
Area of the Tank is in Contact with Water,
A = 2(LH+BH) + LB
(Since, Top surface of water is not in Contact with Tank)
A = 2(30×15+20×15)+30×20
A = 2(450+300)+600
A = 2×750+600
A = 1500+600
A = 2100cm²
i.e., L= 20cm B = 20cm
But Height is 3/4 th ( three-quarters ) of Tank's Height
So, H = 20×3/4 = 15cm
Area of the Tank is in Contact with Water,
A = 2(LH+BH) + LB
(Since, Top surface of water is not in Contact with Tank)
A = 2(30×15+20×15)+30×20
A = 2(450+300)+600
A = 2×750+600
A = 1500+600
A = 2100cm²
Pavantiwari21:
thanks a lot bro for helping me
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