friends plez plez help me in this que...
for what values of n th term of two Aps
63,65,67....and 3, 10,17, .... equal.
atharv33:
hii
Answers
Answered by
2
Hey user here is your answer.....
----->1st A.P---> 63,65,67
a=63
◆d=65-63=2
An=a+(n-1)d
An=63+(n-1)2
For 2nd A.P
◆a=3
◆d=10-3
◆d=7
An=a+(n-1)d
◆An=3+(n-1)7
According to question
63+(n-1)2=3+(n-1)7
◆63+2n-2=3+7n-7
◆61+2n=7n-4
◆61+4=7n-2n
◆65=5n
◆n=65/5
◆n=13
So 13th. term will be equal
Thanks☺️
.#Rohan
----->1st A.P---> 63,65,67
a=63
◆d=65-63=2
An=a+(n-1)d
An=63+(n-1)2
For 2nd A.P
◆a=3
◆d=10-3
◆d=7
An=a+(n-1)d
◆An=3+(n-1)7
According to question
63+(n-1)2=3+(n-1)7
◆63+2n-2=3+7n-7
◆61+2n=7n-4
◆61+4=7n-2n
◆65=5n
◆n=65/5
◆n=13
So 13th. term will be equal
Thanks☺️
.#Rohan
Answered by
3
(1)
Given AP is 63,65,67....
Let a be the First term and d be the common difference.
First term a = 63
Common difference d = 65 - 63 = 2.
We know that nth term of the ap an = a + (n - 1) * d
= 63 + (n - 1) * 2
= 63 + 2n - 2
= 61 + 2n. ---------- (i)
(2)
Given AP is 3,10,17...
First term a = 3.
Common difference d = 10 - 3 = 7
We know that nth term an = a + (n - 1) * d
= 3 + (n - 1) * 7
= 3 + 7n - 7
= 7n - 4 ------------------- (ii).
Given that nth term of two Ap's are equal.
61 + 2n = 7n - 4
5n = 65
n = 13
Hope this helps!
Given AP is 63,65,67....
Let a be the First term and d be the common difference.
First term a = 63
Common difference d = 65 - 63 = 2.
We know that nth term of the ap an = a + (n - 1) * d
= 63 + (n - 1) * 2
= 63 + 2n - 2
= 61 + 2n. ---------- (i)
(2)
Given AP is 3,10,17...
First term a = 3.
Common difference d = 10 - 3 = 7
We know that nth term an = a + (n - 1) * d
= 3 + (n - 1) * 7
= 3 + 7n - 7
= 7n - 4 ------------------- (ii).
Given that nth term of two Ap's are equal.
61 + 2n = 7n - 4
5n = 65
n = 13
Hope this helps!
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