Question

friends plez plez help me in this que...

for what values of n th term of two Aps
63,65,67....and 3, 10,17, .... equal.

Answer 1

Hey user here is your answer.....


----->1st A.P---> 63,65,67

a=63
◆d=65-63=2

An=a+(n-1)d
An=63+(n-1)2

For 2nd A.P

◆a=3

◆d=10-3
◆d=7
An=a+(n-1)d

◆An=3+(n-1)7

According to question

63+(n-1)2=3+(n-1)7


◆63+2n-2=3+7n-7

◆61+2n=7n-4

◆61+4=7n-2n

◆65=5n

◆n=65/5

◆n=13

So 13th. term will be equal


Thanks☺️
.#Rohan

Answer 2

(1) 

Given AP is 63,65,67....

Let a be the First term and d be the common difference.

First term a = 63

Common difference d = 65 - 63 = 2.

We know that nth term of the ap an = a + (n - 1) * d

                                                             = 63 + (n - 1) * 2

                                                             = 63 + 2n - 2

                                                             = 61 + 2n.   ---------- (i)



(2) 

Given AP is 3,10,17...

First term a = 3.

Common difference d = 10 - 3 = 7

We know that nth term an = a + (n - 1) * d

                                            = 3 + (n - 1) * 7

                                            = 3 + 7n - 7

                                            = 7n - 4   ------------------- (ii).



Given that nth term of two Ap's are equal.

61 + 2n = 7n - 4

5n = 65

n = 13


Hope this helps!