Question

friends pls muze 10 std ke science 1 periodic table ki saari electronic configuration chahiye pls jaldi answer bhejo ​

Answer 1

Answer:

Electronic Configuration of elements

(1) Electronic Configuration of H (Hydrogen)

Atomic number = 1

Electronic configuration: 1s1

Or, 1

Valence electrons = 1

(2) Electronic Configuration of He (Helium)

Atomic number = 2

Electronic configuration: 1s2

Or, 2

Valence electrons = 0

(Because He(helium) is an inert gas, and hence valence electros = 0)

(3) Electronic Configuration of Li (Lithium)

Atomic number = 3

Electronic configuration 1s22s1

Or, 2, 1

Or, [He] 1

Or, [He] 2s1

Valence electrons = Electrons in outermost orbit = 1

(4) Electronic Configuration of Be (Beryllium)

Atomic number: 4

Electronic configuration: 1s22s2

Or, [He] 2

Or, [He] 2s2

Or, 2, 2

Valence electrons = Electrons in outermost orbit = 2

(5) Electronic Configuration of B (Boron)

Atomic number: 5

Electronic configuration: 1s22s22p1

Or, [He] 3

Or, [He] 2s2 2p1

Or, 2, 3

Valence electrons = Number of electrons in outermost orbit = 3

(6) Electronic Configuration of C (Carbon)

Atomic number: 6

Electronic configuration of C(carbon) : 1s22s22p2

Or, [He] 4

Or, [He] 2s2 2p2

Or, 2, 4

Valence electrons of C (Carbon) = Number of electrons in outermost orbit = 4

(7) Electronic Configuration of N (Nitrogen)

Atomic number: 7

Electronic configuration of C(carbon) : 1s22s22p3

Or, [He] 5

Or, [He] 2s2 2p3

Or, 2, 5

Valence electrons of N (Nitrogen) = Number of electrons in outermost orbit = 5

(8) Electronic Configuration of O (Oxygen)

Atomic number: 8

Electronic configuration of O (Oxygen) : 1s22s22p4

Or, [He] 6

Or, [He] 2s2 2p4

Or, 2, 6

Valence electrons of O (Oxygen) = Number of electrons in outermost orbit = 6

(9) Electronic Configuration of F (Fluorine)

Atomic number: 9

Electronic configuration of F (Fluorine) : 1s22s22p5

Or, [He] 7

Or, [He] 2s2 2p5

Or, 2, 7

Valence electrons of F (Fluorine) = Number of electrons in outermost orbit = 7

(10) Electronic Configuration of Ne (Neon)

Atomic number: 10

Electronic configuration of Ne (Neon) : 1s22s22p6

Or, [He] 8

Or, [He] 2s2 2p8

Or, 2, 8

Valence electrons of Ne (Neon) = Number of electrons in outermost orbit = 0

Since, Ne (Neon) is an inert gas, thus valence electrons of Ne (Neon) = 0

Explanation:

follow and Mark as branliest. please I need only 10 branliest answers.