Question

friends pls tell me the solution step by step pls ​

Answer 1

Answer:

answer is 1

Step-by-step explanation:

x*a2-b2. x *b2_c2/x*a2-c2

=x*a2-b2+b2-c2/x*a2-c2

=x*a2-c2\x*a2-c2

=1 is answer

pls mark my answer as brainliest one

Answer 2

Question:-

$\to \: \frac{(x {}^{a + b} ) {}^{a - b} \times (x {}^{b + c}) {}^{b - c} }{( x{}^{a + c} ) {}^{a - c} }$

Solution:-

$\to \: \frac{(x {}^{a + b} ) {}^{a - b} \times (x {}^{b + c}) {}^{b - c} }{( x{}^{a + c} ) {}^{a - c} }$

Use some exponential law

$(x {}^{m} ) {}^{n} = x {}^{m \times n}$

$x {}^{m} \times x {}^{n} = x {}^{m + n}$

$\frac{x {}^{m} }{x {}^{n} } = x {}^{m - n}$

$x {}^{0} = 1$

$\to \: \frac{(x ){}^{(a + b)} {}^{(a - b)} \times (x) {}^{(b + c)}{}^{(b - c)} }{( x){}^{(a + c)} {}^{(a - c)} }$

Use this identity

=> ( a - b )( a + b )=( a² - b² )

By the use of this identity we get

$\to \: \frac{(x ){}^{} {}^{(a {}^{2} - b {}^{2} )} \times (x) {}^{}{}^{(b {}^{2} - c {}^{2} )} }{( x){}^{} {}^{(a {}^{2} - c {}^{2} )} }$

$\to \: \frac{(x ){}^{} {}^{(a {}^{2} - b {}^{2} + } {}^{}{}^{b {}^{2} - c {}^{2} )} }{( x){}^{} {}^{(a {}^{2} - c {}^{2} )} }$

$\to \: \frac{(x ){}^{} {}^{(a {}^{2} - c {}^{2} )} }{( x){}^{} {}^{(a {}^{2} - c {}^{2} )} }$

$\to \: x {}^{a ^{2} - {c}^{2} - {a}^{2} + {c}^{2} }$

$\to \: x {}^{0}$

$\to \: 1$

Answer:- 1