Question

friends plz help me to solve it. ​

Answer 1

Step-by-step explanation:

$x = \sqrt{12 + \sqrt{12 + \sqrt{12}.... } } \\ x = \sqrt{12 + x } \\ {x}^{2} =1 2 + x \\ {x }^{2} - 12x - 12 = 0 \\ x = \frac{12 \: \pm \: \sqrt{144 + 48} }{2} \\ x = 6 + 4 \sqrt{3} \: \: \: \: since \: \: \: \: x > 0$