Question

friends plzzz solve this fast....in ur notebook step by step.... question for 20 points ​

Answer 1

$heya \\ \\ \\ 6th \: term \: of \: this \: g. p \: i s \: \: \: \: \: a \times r {}^{5} \\ \\ \\ where \: a \: is \: \: ist \: term \: and \: \: \: r \: is \: common \: ratio \: \: \: \\ \\ \\ here \: \: \: \: a \: = \sqrt{3} \: \: \: \: \: and \: \\ \\ \\ \\ r = (1 \div \sqrt{3} ) \div ( \sqrt{3}) \\ \\ \\ r = (1 \div \sqrt{3 {}^{2} } ) \\ \\ \\ r = 1 \div 3^5\\ \\ \\ so \: 6th \: term \: of \: this \: g.p \: is \: \: \: \: = \\ \\ \\ \sqrt{3} \times (1 \div 3^5)\\ \\ = \sqrt{3} \div 3^5$

Answer 2

$\sqrt{3} \div (3) {}^{n - 1}$

n th term