Question

friends there is question for you that is Write a balanced chemical equation for the reaction of the gollowing and also name the product formed in each case: (a)Aluminium when heated in air (b)Iron with stream (c)CO2 is passed through lime water (d)Dilute HCl reacts with Aluminium powder (e)Dilute HCl reacts with Na2CO3

Answer 1

STD 10 Mark as brainist please

Answer 2

1) 4Al(s)+3O2(g)-->2Al2O3(s)

product - aluminium oxide

Aluminium oxide is also known as bauxite

hope this might help u in MCQs!

2) When a metal reacts with steam then the products formed are metal oxide and hydrogen gas.
Metal + steam --------> Metal oxide + Hydrogen

When red hot iron reacts with steam to form iron(II,III) oxide and hydrogen.

3Fe(s) + 4H2O(g) steam -------> Fe3O4 (s) + 4H2(g)

3)Lime water is solution of Calcium Hydroxide almost as clear as water When Carbon di oxide gas is passed through it it turns milky because in this chemical reaction Calcium Carbondate is Formed which is insoluble in water So these insoluble particles are spread throughout the solution These particles being white in colour the solution appears to be milky The chemical reaction takes place as follows … …………………

Ca(OH) 2 +CO2————-CaCO3 +H2O

4) With di­lut­ed hy­drochlo­ric acid, alu­minum re­acts at room tem­per­a­ture – no spe­cial con­di­tions for con­duct­ing this re­ac­tion are re­quired. The met­al dis­solves in hy­drochlo­ric acid, as a re­sult of which alu­minum chlo­ride and col­or­less hy­dro­gen gas form. This re­ac­tion is ir­re­versible, as fi­nal prod­ucts form as a re­sult (salt and gas) which do not re­act with each oth­er.

The de­scrip­tion of process is as fol­lows: in the re­ac­tion of metal­lic alu­minum with hy­drochlo­ric acid, an ox­i­da­tion-re­duc­tion re­ac­tion takes place. Alu­minum acts as the re­duc­er, giv­ing up elec­trons:

Al⁰ - 3e = Al³⁺

Cations of hy­drochlo­ric acid take elec­trons, re­duc­ing to molec­u­lar hy­dro­gen:

2H⁺ + 2e = H₂⁰

Com­plete re­ac­tion equa­tion:

2Al⁰ + 6H⁺ + 6Cl⁻ = 2Al³⁺ + 6Cl⁻ + 3H₂⁰

In ab­bre­vi­at­ed ion­ic form:

2Al⁰ + 6H⁺ = 2Al³⁺ + 3H₂⁰

In molec­u­lar form the re­ac­tion looks as fol­lows:

2Al + 6HCl = 2Al­Cl₃ + 3H₂

hope this helps you