Question

frnds pls help me to solve this don't spam plsss​

Answer 1

Answer:

2

Step-by-step explanation:

$2^+$ is slightly more than 2. So The limit can also be written as:

$\lim_{x \to 2^+} [x]=\lim_{h \to 0^+}[2+h]$

This is clearly 2 as h is more than zero but less than 1.

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