Question

frnds plz answer if u answer correctly I will mark as brain list answer​

Answer 1

$cos^{2}60° + sin^{2}30° + tan^{2}60° + tan^{2}60° + tan^{2}30° = 3\dfrac{5}{6}$

$\text{We know , the value of}$ $\text{Trigonometric Ratio's , so}$

$\text{putting the value in the equation ; we get,}$

$\bigg(\dfrac{1}{2}\bigg)^{2} + \bigg(\dfrac{1}{2}\bigg)^{2} + \bigg(\sqrt{3}\bigg)^{2} + \bigg(\sqrt{3}\bigg)^{2} + \bigg(\dfrac{1}{\sqrt{3}}\bigg)^{2} = 3\dfrac{5}{6}$

$\dfrac{1}{4} + \dfrac{1}{4} + 3 + 3 + \dfrac{1}{3} = 3\dfrac{5}{6} = 3\dfrac{5}{6}$

$\dfrac{3 + 3 + 36 + 36 + 4}{12} = 3\dfrac{5}{6}$

$\dfrac{82}{12} = 3\dfrac{5}{6}$

$\dfrac{41}{6} = 3\dfrac{5}{6}$

$6\dfrac{5}{6} = 3\dfrac{5}{6}$

$Thus , LHS ≠ RHS...$