ת וטווחfro
The ages of Radha and Sudha are in the ratio 4:5. Two years from
be in the ratio 5:6. Find their present ages.
Answers
Answer:
Present age of Radha = 8 years
Present age of Sudha = 10 years
Step-by-step explanation:
Given--->
-----------
The present ages of Radha and Sudha are in the ratio 4:5 and two years from now ages be in the ratio 5:6
To find --->
------------
Present ages of Radha and Sudha
Solution--->
---------------
Let present ages of Radha and Sudha be x and y years
ATQ x : y = 4 : 5
=> x / y = 4 / 5
=> x =( 4 / 5) y
After two years age of Radha = x + 2
After two years age of Sudha = y + 2
ATQ (x + 2 ) : ( y + 2 ) = 5 : 6
=> ( x + 2 ) / ( y + 2 ) = 5 / 6
=> 6 ( x + 2 ) = 5 ( y + 2 )
=> 6 x + 12 = 5 y + 10
=> 6x - 5 y = 10 - 12
=> 6x - 5 y = -2
Putting x = 4/5 y in it
=> 6 (4/5 y ) - 5 y = -2
24 y -25 y
=> -------------------- = -2
5
- y
=> --------- = -2
5
=> - y = - 10
=> y = 10
x =( 4/5) y
Putting y = 10 in it
x = (4 / 5 ) 10
= 4 × 2
= 8
Present age of Radha = x
= 8 years
Present age of Sudha = y
= 10 years
SOLUTION:-
Given:
The ages of Radha & Sudha are in the ratio 4:5.Two years from be in the ratio 5:6.
To find:
The present age of Radha and Sudha.
Explanation:
Let the present age of Radha be R years.
Let the present age of Sudha be M years.
Therefore,
R:M=4:5
[Cross Multiplication]
∴According to the question:
- After two years the age of Radha & Sudha :
- Age of Radha after two years= (R+2) years.
- Age of Sudha after two years=(M+2) years.
Then the ratio formed 5:6.
(R+2):(M+2)=5:6
[Cross Multiplication]
→6(R+2)=5(M+2)
→6R+12=5M+10
→6R-5M=10-12
→6R-5M= -2
Using the place of R from equation (1), we get;
Using the value of M in equation (1), we get;
R= 4(10)/5
R= 40/5
R= 8 years
Thus,
- The present age of Radha is 8 years.
- The present age of Sudha is 10 years.