Math, asked by 1964194342, 6 months ago

From 11 names on a ballot, a committee of 6 will be elected to attend a political national convention. How many different committees are possible?

Answers

Answered by Krishnashandilya
0

There are

8

people that could be our first choice;

after this there would be

7

people for our second choice;

and then

6

people for our third choice.

This would give us

8

×

7

×

6

ways of making first, second, and third choices.

But the same three people could form our 3 person committee in multiple ways. e.g. {Alice, Bob, Carol} and {Bob, Carol, Alice} should be considered as the same committee.

How many ways could 3 people be arranged among 3 sequential positions that should be treated as the same committee?

There are

3

possibilities for the first position;

2

for the second; and

1

for the third. So

3

×

2

×

1

=

6

arrangements should be considered the same committee.

Therefore the number of committees (without internal ordering) should be

8

×

7

×

6

3

×

2

×

1

=

5

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