Question

From 150 g of urea (NH2CONH2) when 3 x 1023
molecules are removed then the remaining moles of
urea will be

Answer 1

Answer:

2032

Explanation:

From 150 g of urea (NH2CONH2) when 3 x 1023

molecules are removed then the remaining moles of

Answer 2

Answer:

2 MOLES

Explanation:

given mass= 150g

$moles = \frac{given \: mass}{molar \: mass}$

molar mass of urea= 60

thus, moles = 2.5

molecules=2.5×6.022×10²³(AVOGADRO’S number)

=15.055×10²³

remaining molecules=

(15.055-3)10²³=12.055×10²³

divide by AVOGADRO’S number

moles = 12.055×10²³/6.022×10²³

thus moles = 2 moles approx.

hope it helps:)