Question

From 160 g of SO,(g) sample, 1.2046 x 1024 molecules of So, are removed then find out the volume of
left over SO2(g) at STP.​

Answer 1

Explanation:

1.2046×10

24

molecules of SO

2

=

6.023×10

23

1.2046×10

24

=2 mole of SO

2

160 gram SO

2

contains 2.5 mole SO

2

and 2 moles are removed

So, 0.5 moles are remaining.

Volume of one mole of SO

2

at STP is 22.4 litre

Therefore volume of 0.5 mole of SO

2

is 22.4/2 =11.2 litre

hope its helpful

Answer 2

Answer:

Volume=11.2 liters

Explanation:

See the explanation in the attachment.