From 160 g of SO,(g) sample, 1.2046 x 1024 molecules of So, are removed then find out the volume of
left over SO2(g) at STP.
Answers
Answered by
2
Explanation:
1.2046×10
24
molecules of SO
2
=
6.023×10
23
1.2046×10
24
=2 mole of SO
2
160 gram SO
2
contains 2.5 mole SO
2
and 2 moles are removed
So, 0.5 moles are remaining.
Volume of one mole of SO
2
at STP is 22.4 litre
Therefore volume of 0.5 mole of SO
2
is 22.4/2 =11.2 litre
hope its helpful
Answered by
2
Answer:
Volume=11.2 liters
Explanation:
See the explanation in the attachment.
Attachments:
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