Question

From 1980 to 1990 , lior's weight increased by 25% . If his weight was k kilograms in 1990, what was it in 1980?

Answer 1

Answer:

Step-by-step explanation:

25% of k is 25k/100

Therefore his weight at 1980 would be k-25k/100

=100k-25k/100

=75k/100

Answer 2

Answer: The weight of Lior's in 1990  $\dfrac{3k}{4}$

Step-by-step explanation:

Lior's weight  in 1980 = k

Increased weight = 25%

Therefore the weight of lior's in 1990  is given by

$k+ 25\% \text { of } k = k- \dfrac{25}{100} \times k = k- \dfrac{1}{4} k\\\\= \dfrac{3k}{4}$

Hence, the weight of Lior's in 1990  $\dfrac{3k}{4}$