Question

From 200 mg of CO, when x molecules are removed,
2.89 x 10-3 moles of CO2 are left. x will be ?​

Answer 1

10²¹ molecules

Explanation:

Moles of CO2 =

$\frac{200 \times {10}^{ - 3} }{44} = 4.54 \times {10}^{ - 3} moles$

Moles removed =

$4.54 - {10}^{ - 3} - 2.89 \times {10}^{ - 3} = 1.65 \times {10}^{ - 3}$

Therefore moles removed =

$1.65 \times {10}^{ - 3} \times 6.022 \times {10}^{23} \\ = 10 \times {10}^{20} \\ {10}^{21}$

Hope I helped you! :)

Answer 2

Explanation:

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