Question

From 200 mg of CO2,10^21 molecules are removed. How many moles of CO2 are left

Answer 1

200mg=(200×6.023×10^23)/44000
=2.7378×10^21
so molecules left=(2.7378×10^21-10^21)
=1.7378

Answer 2

Answer:

One mole of atoms =6.023×10

23

atoms = Gram atomic mass of element

44 grams of CO

2

=1moleCO

2

=6×10

23

molecules of CO

2

200mg=

44×1000

200×1

moles=

44×1000

200×10

23

×6.023 molecular of CO

2

=27.37×10

20

molecular of CO

2

=2.737×10

21

molecules of CO

2

molecules left =1.737×10

21

molecular of CO

2

moles of CO

2

left =

6.023×10

23

1.737×10

4

=0.29×10

−2

moles of CO

2

=2.9 mill moles